2x^2+0,16x+6=0

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Solution for 2x^2+0,16x+6=0 equation: 



2x^2+0.16x+6=0

a = 2; b = 0.16; c = +6;
Δ = b2-4ac
Δ = 0.162-4·2·6
Δ = -47.9744
Delta is less than zero, so there is no solution for the equation

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